Spermy's Adventure: Quest for the Egg
A downloadable game for Windows
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an odd rpg where you play as a sperm and go on a wonderful quest to fertilize the egg.
https://oilybastard.bandcamp.com/album/spermys-adventure-quest-for-the-egg-sound...
Status | Released |
Platforms | Windows |
Author | oilybastard |
Genre | Role Playing |
Tags | Pixel Art, RPG Maker, Short, weird |
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Click download now to get access to the following files:
Spermy's Adventure Quest for the Egg.zip 202 MB
Comments
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this game is so so so good. i highly recommend preparing more for the final boss fight at the egg. i stupidly used all of my biggest fructose clumps on the blue
ballsphere gatekeeper, but the final boss can do like 50 hp of damage so i kept needing to revive and regenerate iii-ing. my only qualm with this game is if everyone in your party dies, the entire game is lost. so, just save frequently and alt+f4. the game also sometimes froze when i touched a sperm on a ladder in the third blue sphere level, and i had to close the game. the soundtrack is poggers, the graphics are poggers, the gameplay is poggers, and the party combat system is poggers. on the beach with the sailors, i highly recommend investing the $190 in the sharp flagellum and equipping it, since that's the last business sperm for a bit. thank you for making this masterpiece.THANK YOU
This is so dumb but its alright until the ship where it's really annoying
i cant figure out the puzzle for the ship
you need to find the ten digits and then apply the extra rules the one guy gives you (like removes certain digits) sorry i made it so complicated
hi it was a bit annoying but the code is 4 9 5 5 2 4 9. more specifically,
d1 = 3
d2 = 6
d3 =1 = (d1 = 3) - (d7 = 2)
d4 = 9
d5 = 5 [11th digit of (pi = 3.1415926535)]
d6 = 5 = {[(d1 = 3) + (d2 = 6) + (d3 = 1)] / 2}
d7 = 2
d8 = 4 = [(d1+d2+d3+d4+d5+d6+d7+d9+d10) - 39]
d9 = 9
d10 = (d1 = 3)
and the code is just {(d3+d10), d4, d5, d6, d7, d8, d9}
hope that helps! and to anyone else who doesn't want spoilers, just ... don't remember the code from this comment :)